f(x)=[1/(2^x-1)+1/2]*x^3,分母不能为零,2^x-1不为零,x不等于零,
f(-x)=[1/(2^-x-1)+1/2]*-x^3负负得正,
=[1/(1-2^-x)-1/2]*x^3
=[2^x/(2^x-1)-1/2]*x^3
=[2^x/(2^x-1)-1+1/2]x^3通分
=[1/(2^x-1)+1/2]x^3
打字太难了.
已知函数f（x）=（1/（2的x方-1）+1/2)x的3方
f(x)=[1/(2^x-1)+1/2]*x^3,分母不能为零,2^x-1不为零,x不等于零,
f(-x)=[1/(2^-x-1)+1/2]*-x^3负负得正,
=[1/(1-2^-x)-1/2]*x^3
=[2^x/(2^x-1)-1/2]*x^3
=[2^x/(2^x-1)-1+1/2]x^3通分
=[1/(2^x-1)+1/2]x^3
打字太难了.