Question

若(x^2+1)(x+3)^9=a0+a1(x-2)+a2(x-2)^2+a3(x-2)^3+…+a11(x-2)^11

Answer 1

令x=3,则（3^2+1)(3+3)^9=10*6^9=ao+a1+a2+……+a11

令x=2,则（2^2+1)(2+3)^9=5*5^9=a0

两式相减得a1+a2+……a11=10*6^9-5^10