积分区间即与x轴的两个交点
-1/2x^2+2=0 解得x=2,-2
则面积为:
∫(1/2x^2+2)dx 积分区间[-2 2]
=1/6x^3+2x|x=2 - 1/6x^3+2x|x=-2
=1/6(2^3-(-2)^3)+2(2+2)
=32/3
积分区间即与x轴的两个交点
-1/2x^2+2=0 解得x=2,-2
则面积为:
∫(1/2x^2+2)dx 积分区间[-2 2]
=1/6x^3+2x|x=2 - 1/6x^3+2x|x=-2
=1/6(2^3-(-2)^3)+2(2+2)
=32/3