Question

设函数F(x)=-x(x-m)的平方,m=1时,求曲线y=(x)在点(2,f(2))处的切线方程

Answer 1

f(x)=-x(x-1)=-x^2+x

f(2)=-4+2=-2

f'(x)=-2x+1

f'(2)=-4+1=-3

切线:y-(-2)=-3(x-2)化简

y=-3x+4