(2/3)+(5/9)+(8/27)+(11/81)+(14/243)+...+[(3n-1)/(3^n)]

2个回答

  • 设Sn=2/3+5/9+8/27+11/81+14/243+...+(3n-1)/(3^n)

    ∴1/3Sn=2/9+5/27+8/81+11/243+...+(3n-4)/(3^n)+(3n-1)/3^(n+1)

    ∴Sn-1/3Sn=2/3Sn

    =2/3+3/9+3/27+3/81+.+3/3^n-(3n-1)/3^(n+1)

    =2/3-(3n-1)/3^(n+1)+[1/3+1/9+1/27+...+1/3^(n-1)]

    =2/3-(3n-1)/3^(n+1)+1/3[1-(1/3)^(n-1)]/(1-1/3)

    =2/3-(3n-1)/3^(n+1)+1/2[1-1/3^(n-1)]

    =7/6-(3n-1)/3^(n+1)-(9/2)/3^(n+1)

    =7/6-(3n+7/2)/3^(n+1)

    ∴Sn=7/4-(6n+7)/(4×3^n)