电磁波的波速c=3×10 8m/s,某红外线的波长λ=0.01mm=1×10 -5m,
根据c=λf得:
f=
c
λ =
3× 10 8 m/s
1× 10 -5 m =3×10 13Hz=3×10 7MHz
故答案为:3×10 13,3×10 7.
电磁波的波速c=3×10 8m/s,某红外线的波长λ=0.01mm=1×10 -5m,
根据c=λf得:
f=
c
λ =
3× 10 8 m/s
1× 10 -5 m =3×10 13Hz=3×10 7MHz
故答案为:3×10 13,3×10 7.