Question

解方程x^2+3-根号(2x^2-3x+2)=3(x+1)/2

Answer 1

x^2+3-根号(2x^2-3x+2)=3(x+1)/2

2x^2-3x+3-2根号(2x^2-3x+2)=0

换元:a=根号(2x^2-3x+2)>=0

a^2-2a+1=0

a=1

根号(2x^2-3x+2)=1

2x^2-3x+2=1

2x^2-3x+1=0

x=1 或1/2