1 已知圆C的圆心再直线Y=2X上,圆C截Y轴所得的玄长为6.且与X轴相切,试求圆C的方程.

1个回答

  • 1. 设圆心为(a, b), 圆半径为r, 圆的方程为: (x-a)^2 + (y-b)^2 = r^2 (1)

    圆心(a, b)在直线y=2x上, b = 2a (2)

    圆与X轴相切, 切点为(a, 0). 切点在圆上: (a - a)^2 + (0-b)^2 = r^2 (3)

    由(3), b^2 = r^2 , b=r 或 b= -r

    A. b = r, 由(2), a = r/2

    圆C与Y轴的交点的横坐标为0, 代入(1): (0-r/2)^2 +(y - r)^2 = r^2

    (y-r)^2 = 3r^2/4

    y = (1±√3/2)r

    交点的坐标为(0, (1+√3/2)r), (0, (1-√3/2)r)

    其距离为(弦长): (1+√3/2)r - (1-√3/2)r = 6

    √3r = 6

    r = 2√3

    b = 2√3; a = √3

    圆的方程为: (x - √3)^2 + (y - 2√3)^2 = 12

    B. b = -r, 由(2), a = -r/2

    与A类似, r = 2√3, b = -2√3; a = -√3

    圆的方程为: (x + √3)^2 + (y + 2√3)^2 = 12

    2. 设圆心为(a, b), 圆半径为r, 圆的方程为: (x-a)^2 + (y-b)^2 = r^2

    圆过原点: a^2 + b^2 = r^2 (1)

    圆过点(1, 1): (1- a)^2 + (1-b)^2 = r^2 (2)

    由(1)(2): a^2 + b^2 = (1- a)^2 + (1-b)^2

    a + b = 1 (3)

    圆与X轴的交点的纵坐标为0, 代入圆的方程: (x - a)^2 + (0 - b)^2 = r^2

    (x-a)^2 = r^2 - b^2

    x = a ± √(r^2 - b^2)

    交点的横坐标为: a + √(r^2 - b^2), a - √(r^2 - b^2)

    其距离为(弦长): 2√(r^2 - b^2) = 3

    r^2 - b^2 = 9/4

    r^2 = b^2 + 9/4 (4)

    将(4)代入(1): a^2 + b^2 = b^2 + 9/4

    a^2 = 9/4

    a = ±3/2

    A. a = 3/2, b = 1-3/2 = -1/2, r^2 = 1/4 + 9/4 = 5/2

    圆的方程为: (x -3/2)^2 + (y + 1/2)^2 = 5/2

    B. a = -3/2, b = 1 + 3/2 = 5/2, r^2 = 25/4 + 9/4 = 17/2

    圆的方程为: (x + 3/2)^2 + (y - 5/2)^2 = 17/2

    3. C1:x²+y²-2x=0, (x-1)^2 + y^2 = 1

    圆心为(1, 0), 圆半径为1

    直线L:x+√3y=0, y = -x/√3, 斜率为 -1/√3.

    设圆C圆心为(a, b), 圆半径为r: (x - a)^2 + (y - b)^2 = r^2 (1)

    圆C与直线L:x+√3y=0相切于点P(3,-√3), CP垂直于直线L, 过CP的直线M斜率为 √3. 设M的方程为 y = √3x + c

    M过点P(3,-√3), c= -4√3

    M的方程为 y = √3x -4√3

    M过点C: b = √3a -4√3 = √3(a -4) (2)

    C: (a, √3(a -4))

    CC1距离为两圆半径之和: (a -1)^2 + [√3(a -4)]^2 = (r+1)^2

    (a-1)^2 + 3(a-4)^2 = (r+1)^2 (3)

    圆C过点P: (a - 3)^2 + [ (√3(a -4) + √3]^2 = r^2 (4)

    (3) -(4)并化简可得: r = 6 - a (5)

    (5)代入(3)并化简: a^2 -4a = 0, a(a-4) = 0

    a = 0 或 a = 4

    A. a = 0, r = 6, b = -4√3

    圆C的方程为: x^2 + (y+4√3)^2 = 36

    B. a = 4, r = 2, b = 0

    圆C的方程为: (x-4)^2 + y^2 = 4