y=ln(x-√(1+x^2)) 求dy/dx
1个回答
设u=x-√(1+x^2)
dy/du=1/u
du/dx=1-x/√(1+x^2)
dy/dx=[1-x/√(1+x^2)]/[x-√(1+x^2)] =-1/√(1+x^2)
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