设两根是x1,x2,两根都大于1,那么有:
b^2-4ac>=0 (i)
(x1-1)(x2-1)>0 (ii)
x1+x2>2 (iii)
又x1x2=c/a>1>0
=>c>0
(ii)=>x1x2-(x1+x2)+1>0
=>c/a+b/a+1>0
=>a+b+c>a
=>b+c>0
=>b>-c
(iii)=>-b/a>2
=
设两根是x1,x2,两根都大于1,那么有:
b^2-4ac>=0 (i)
(x1-1)(x2-1)>0 (ii)
x1+x2>2 (iii)
又x1x2=c/a>1>0
=>c>0
(ii)=>x1x2-(x1+x2)+1>0
=>c/a+b/a+1>0
=>a+b+c>a
=>b+c>0
=>b>-c
(iii)=>-b/a>2
=