Question

若3X-7=-1的解比ay-b+1=-c的解的3倍少1,求（A-B+C)的2011次方

Answer 1

3X-7=-1

3x = 6

x = 2

ay-b+1=-c

ay = b-c-1

y = (b-c-1)/a

3倍少1

即 x = 3y-1

2 = 3(b-c-1)/a -1

3 = 3(b-c-1)/a

a = b-c-1

a-b+c = -1

(a-b+c)^2011 = -1

即 （A-B+C)的2011次方 等于 -1