2π<x<3π π<x/2<3π/3 sin(x2) + cos(x2)
求sinx=(1\3),2π<x<3π,那么sin(x\2) + cos(x\2)
3个回答
相关问题
-
f(x)sinx·sin(π-x)+√3sin(π/2+x)cos(π/2+x)+2cos(π+x)cos(π-x) 求
-
cos[x+(π/4)]=(√2)/10,x∈(π/2,3π/4),求sinx和sin[2x+(π/3)].
-
求函数y=[sin2x+sin(2x+π/3)-cos1/2﹙π-4x﹚]/[cos2x+cos﹙2x+π/3﹚-sin
-
若sin(x-π)=2cos(2π-x),求(sin(π-x)+5cos(2π-x))/(3cos(π-x)-sin(-
-
已知cos(x-π/4)=√2/10,x∈(π/2,3π/4),1.求sinx 2.求sin(2x+π/3)的值
-
已知sinx=-1/3,x∈(π,3π/2),求sin(2x-45)和cos(2x+45)求过程
-
已tanx=4/3,求cos(2x-π/3)cos(π/3-x)-sin(2x-π/3)sin(π/3-x)
-
sinx+sin(x+2/3π)+sin(x-2/3π)
-
已知√3sinx-(sin( π/2-2x))/(cos( π+x))*cosx=1,x属于(0,π) 求x的值
-
已知f(x)=sin(x−3π)•cos(2π−x)•sin(−x+3π2)cos(−x−π)•cos(π2−x)