x/2=y/3
x=2y/3
(3x+2y)/(2x-3y)
=[3(2y/3)+2y]/[2(2y/3)-3y]
=4y/(-5y/3)
=-12/5
已知x/2=y/3,求分式(3x+2y)/(2x-3y)的值.
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