初三数学题某件商品进价为6元,若每件9元售卖,每天可卖100件,根据市场调查,

2个回答

  • 设每件售价为x元,可获利润为y元,有题意得

    y=【100-(x-9)×5】×(x-6)

    =(100-5x+45)(x-6)

    =-5x²+175x-870

    x=-b/2a

    =-175/-10

    =17.5

    y=4ac-b²/4a

    =-13225/-20

    =661.25