1,lg25+2/3lg8+lg5*lg20+lg^22
=2lg5+2lg2+lg5*(2lg2+lg5)+lg2*lg2
=2(lg5+lg2)+(lg5)^2+2lg2*lg5+(lg2)^2
=2lg10+(lg5+lg2)^2
=2+1^2
=3
2,设f(x)=ax+b
3f(x+1)-2f(x-1)
=3a(x+1)+3b-［2a(x-1)+2b］
=3ax+3a+3b-2ax+2a-2b
=ax+5a+b
=2x+17
所以,a=2
5a+b=17,b=7
f(x)=2x+7
1.计算：lg 25+2/3lg 8+lg 5×lg 20+lg^(2) 2
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