Question

二次根式的乘除计算题,1)根号28*根号72）根号4分之1*根号2563）4根号xy 乘 根号y分之14）6根号27*（

Answer 1

答：

1)根号28*根号7

=√28*√7

=√4*√7*√7

=2*7

=14

2）根号4分之1*根号256

=√(1/4)*√(256)

=√(256/4)

=√64

=8

3）4根号xy 乘 根号y分之1

=4√(xy)*√(1/y)

=4√(xy/y)

=4√x

4）6根号27*（-2根号3）

=6√27*(-2√3)

=-2*6*√9*√3*√3

=-12*3*3

=-108