x3+x2+12x=0 (28 19:28:51)
7个回答
x³+x²+12x
=x(x²+x+12)=0
所以x1=0或者x²+x+12=0
对于后面,△
相关问题
6x+3x=13.51.x+0.3x=248x-3x=21.05x+2x=907.7+3x=12.28*2.5-2x=1
x-0.8x=28 2x+12=12
5x-3*(28-x)=12+2x
(x^2-x-2)(x^2+11x+28)-19
解下面的比例.(l)x:12=0.5: 1 3 (2) 15 x = 3.5 28 (3)x:6=0.7:0.28 (4
28.12 9.2812 28.28fx=x12 x根9
2/1x-28=50 4x+3/2=4/5 x-7/2x=28/15 3x-1.2=3.6 0.9x+1.3x=5.28
28:(x-28)=(x+3):(2x-3)怎么解
(1) 3x ²-8x-3 (2)12x ²-11x-15 (3)-12x ²-28+5
X^2-X-28=0