Question

(x^2-x-6分之x^2-4+x-3分之x+2)除以x-3分之x+1

Answer 1

x^2-x-6分解因式得(x+2)(x-3)

x^2-4分解因式得(x-2)(x+2)

故(x^2-x-6分之x^2-4+x-3分之x+2)=(x-2)/(x-3)+(x+2)/(x-3)=2x/(x-3)

原式子=(2x/(x-3))/((x+1)/(x-3))=2x/(x+1)