求200道初二上因式分解题,

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  • 因式分解3a3b2c-6a2b2c2+9ab2c3=3ab^2 c(a^2-2ac+3c^2) 3.因式分解xy+6-2x-3y=(x-3)(y-2) 4.因式分解x2(x-y)+y2(y-x)=(x+y)(x-y)^2 5.因式分解2x2-(a-2b)x-ab=(2x-a)(x+b) 6.因式分解a4-9a2b2=a^2(a+3b)(a-3b) 7.若已知x3+3x2-4含有x-1的因式,试分解x3+3x2-4=(x-1)(x+2)^2 8.因式分解ab(x2-y2)+xy(a2-b2)=(ay+bx)(ax-by) 9.因式分解(x+y)(a-b-c)+(x-y)(b+c-a)=2y(a-b-c) 10.因式分解a2-a-b2-b=(a+b)(a-b-1) 11.因式分解(3a-b)2-4(3a-b)(a+3b)+4(a+3b)2=[3a-b-2(a+3b)]^2=(a-7b)^2 12.因式分解(a+3)2-6(a+3)=(a+3)(a-3) 13.因式分解(x+1)2(x+2)-(x+1)(x+2)2=-(x+1)(x+2) abc+ab-4a=a(bc+b-4) (2)16x2-81=(4x+9)(4x-9) (3)9x2-30x+25=(3x-5)^2 (4)x2-7x-30=(x-10)(x+3) 35.因式分解x2-25=(x+5)(x-5) 36.因式分解x2-20x+100=(x-10)^2 37.因式分解x2+4x+3=(x+1)(x+3) 38.因式分解4x2-12x+5=(2x-1)(2x-5) 39.因式分解下列各式: (1)3ax2-6ax=3ax(x-2) (2)x(x+2)-x=x(x+1) (3)x2-4x-ax+4a=(x-4)(x-a) (4)25x2-49=(5x-9)(5x+9) (5)36x2-60x+25=(6x-5)^2 (6)4x2+12x+9=(2x+3)^2 (7)x2-9x+18=(x-3)(x-6) (8)2x2-5x-3=(x-3)(2x+1) (9)12x2-50x+8=2(6x-1)(x-4) 40.因式分解(x+2)(x-3)+(x+2)(x+4)=(x+2)(2x-1) 41.因式分解2ax2-3x+2ax-3= (x+1)(2ax-3) 42.因式分解9x2-66x+121=(3x-11)^2 43.因式分解8-2x2=2(2+x)(2-x) 44.因式分解x2-x+14 =整数内无法分解 45.因式分解9x2-30x+25=(3x-5)^2 46.因式分解-20x2+9x+20=(-4x+5)(5x+4) 47.因式分解12x2-29x+15=(4x-3)(3x-5) 48.因式分解36x2+39x+9=3(3x+1)(4x+3) 49.因式分解21x2-31x-22=(21x+11)(x-2) 50.因式分解9x4-35x2-4=(9x^2+1)(x+2)(x-2) 51.因式分解(2x+1)(x+1)+(2x+1)(x-3)=2(x-1)(2x+1) 52.因式分解2ax2-3x+2ax-3=(x+1)(2ax-3) 53.因式分解x(y+2)-x-y-1=(x-1)(y+1) 54.因式分解(x2-3x)+(x-3)2=(x-3)(2x-3) 55.因式分解9x2-66x+121=(3x-11)^2 56.因式分解8-2x2=2(2-x)(2+x) 57.因式分解x4-1=(x-1)(x+1)(x^2+1) 58.因式分解x2+4x-xy-2y+4=(x+2)(x-y+2) 59.因式分解4x2-12x+5=(2x-1)(2x-5) 60.因式分解21x2-31x-22=(21x+11)(x-2) 61.因式分解4x2+4xy+y2-4x-2y-3=(2x+y-3)(2x+y+1) 62.因式分解9x5-35x3-4x=x(9x^2+1)(x+2)(x-2) 63.因式分解下列各式: (1)3x2-6x=3x(x-2) (2)49x2-25=(7x+5)(7x-5) (3)6x2-13x+5=(2x-1)(3x-5) (4)x2+2-3x=(x-1)(x-2) (5)12x2-23x-24=(3x-8)(4x+3) (6)(x+6)(x-6)-(x-6)=(x-6)(x+5) (7)3(x+2)(x-5)-(x+2)(x-3)=2(x-6)(x+2) (8)9x2+42x+49=(3x+7)^2 .1.若(2x)n81 = (4x2+9)(2x+3)(2x3),那么n的值是( ) A.2 B. 4 C.6 D.8 2.若9x212xy+m是两数和的平方式,那么m的值是( ) A.2y2 B.4y 2 C.±4y2 D.±16y2 3.把多项式a4 2a2b2+b4因式分解的结果为( ) A.a2(a22b2)+b4 B.(a2b2)2 C.(ab)4 D.(a+b)2(ab)2 4.把(a+b)24(a2b2)+4(ab)2分解因式为( ) A.( 3ab)2 B.(3b+a)2 C.(3ba)2 D.( 3a+b)2 5.计算:()2001+()2000的结果为( ) A.()2003 B.()2001 C. D. 6.已知x,y为任意有理数,记M = x2+y2,N = 2xy,则M与N的大小关系为( ) A.M>N B.M≥N C.M≤N D.不能确定 7.对于任何整数m,多项式( 4m+5)29都能( ) A.被8整除 B.被m整除 C.被(m1)整除 D.被(2n1)整除 8.将3x2n6xn分解因式,结果是( ) A.3xn(xn+2) B.3(x2n+2xn) C.3xn(x2+2) D.3(x2n2xn) 9.下列变形中,是正确的因式分解的是( ) A. 0.09m2 n2 = ( 0.03m+ )( 0.03m) B.x210 = x291 = (x+3)(x3)1 C.x4x2 = (x2+x)(x2x) D.(x+a)2(xa)2 = 4ax 10.多项式(x+yz)(xy+z)(y+zx)(zxy)的公因式是( ) A.x+yz B.xy+z C.y+zx D.不存在 11.已知x为任意有理数,则多项式x1x2的值( ) A.一定为负数 B.不可能为正数 C.一定为正数 D.可能为正数或负数或零 二、解答题: 分解因式: (1)(ab+b)2(a+b)2 (2)(a2x2)24ax(xa)2 (3)7xn+114xn+7xn1(n为不小于1的整数) 答案: 一、选择题: 1.B 说明:右边进行整式乘法后得16x481 = (2x)481,所以n应为4,答案为B. 2.B 说明:因为9x212xy+m是两数和的平方式,所以可设9x212xy+m = (ax+by)2,则有9x212xy+m = a2x2+2abxy+b2y2,即a2 = 9,2ab = 12,b2y2 = m;得到a = 3,b = 2;或a = 3,b = 2;此时b2 = 4,因此,m = b2y2 = 4y2,答案为B. 3.D 说明:先运用完全平方公式,a4 2a2b2+b4 = (a2b2)2,再运用两数和的平方公式,两数分别是a2、b2,则有(a2b2)2 = (a+b)2(ab)2,在这里,注意因式分解要分解到不能分解为止;答案为D. 4.C 说明:(a+b)24(a2b2)+4(ab)2 = (a+b)22(a+b)[2(ab)]+[2(ab)]2 = [a+b2(ab)]2 = (3ba)2;所以答案为C. 5.B 说明:()2001+()2000 = ()2000[()+1] = ()2000 = ()2001 = ()2001,所以答案为B. 6.B 说明:因为MN = x2+y22xy = (xy)2≥0,所以M≥N. 7.A 说明:( 4m+5)29 = ( 4m+5+3)( 4m+53) = ( 4m+8)( 4m+2) = 8(m+2)( 2m+1). 8.A 9.D 说明:选项A,0.09 = 0.32,则 0.09m2 n2 = ( 0.3m+n)( 0.3mn),所以A错;选项B的右边不是乘积的形式;选项C右边(x2+x)(x2x)可继续分解为x2(x+1)(x1);所以答案为D. 10.A 说明:本题的关键是符号的变化:zxy = (x+yz),而xy+z≠y+zx,同时xy+z≠(y+zx),所以公因式为x+yz. 11.B 说明:x1x2 = (1x+x2) = (1x)2≤0,即多项式x1x2的值为非正数,正确答案应该是B. 二、解答题: (1) 答案:a(b1)(ab+2b+a) 说明:(ab+b)2(a+b)2 = (ab+b+a+b)(ab+bab) = (ab+2b+a)(aba) = a(b1)(ab+2b+a). (2) 答案:(xa)4 说明:(a2x2)24ax(xa)2 = [(a+x)(ax)]24ax(xa)2 = (a+x)2(ax)24ax(xa)2 = (xa)2[(a+x)24ax] = (xa)2(a2+2ax+x24ax) = (xa)2(xa)2 = (xa)4. (3) 答案:7xn1(x1)2 说明:原式 = 7xn1 x27xn1 2x+7xn1 = 7xn1(x22x+1) = 7xn1(x1)2.我不知道 够不够 . 不过200道,这个数字有点天文.不是本来人想的.