∵2sin60°+2cos45°+1=2×
3
2 +2×
2
2 +1=
3 +
2 +1,
∴
x+3
x+2 =
1
3 +
2 +1 ,
解得x=-3-
3 +
2 ,
∴
x-3
2x-4 ÷(
5
x-2 -x-2) =
x-3
2(x-2) ÷
5-(x+2)(x-2)
x-2 ,
=
x-3
2(x-2) ×
x-2
9- x 2 ,
=-
1
2(x+3) ,
=-
1
2(-3-
3+
2 +3 ) ,
=
3 +
2
2 .
故答案为:
3 +
2
2 .
∵2sin60°+2cos45°+1=2×
3
2 +2×
2
2 +1=
3 +
2 +1,
∴
x+3
x+2 =
1
3 +
2 +1 ,
解得x=-3-
3 +
2 ,
∴
x-3
2x-4 ÷(
5
x-2 -x-2) =
x-3
2(x-2) ÷
5-(x+2)(x-2)
x-2 ,
=
x-3
2(x-2) ×
x-2
9- x 2 ,
=-
1
2(x+3) ,
=-
1
2(-3-
3+
2 +3 ) ,
=
3 +
2
2 .
故答案为:
3 +
2
2 .