Question

设浮点数的格式为：阶码4位,包含一位符号位,尾数5位,包含一位符号位,阶码和尾数均用补码表示,则

Answer 1

解答第1题：

.

x =22/64 =10110b/2^6

将10110b右移6位：

x = 0.010110b

规格化：x =0.10110bx(2^-1)

[x阶]原 =1001b

[x阶]反 =1110b

[x阶]补 =1111b

[x尾]补 =01011b

x浮 =1111,01011b

.

y = -2.75 = -(2+3/4) = -(10b +0.11b) = -10.11b

规格化：y = -0.1011bx(2^2)

[y阶]补 =0010b

[y尾]原 =11011b

[y尾]反 =10100b

[y尾]补 =10101b

y浮 =0010,10101b

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