Question

两块竖直方向木板间夹着一个重为20N的金属块A,压力N＝100N,动摩擦因数μ=0.15

Answer 1

1.G+F拉=F摩 F拉=100*0.15*2N-20N=10N

2.F拉-G=F摩 F拉=100*0.15*2N+20N=50N