计算 sin10°^2 + sin50°^2 + sin10°sin50° 的值? 答案:3/4

3个回答

  • 原式=(1-cos20)/2+(1-coxs100)/2+sin10sin(10+40)

    =1-1/2(cos20+cosx100)+sin10^2cos40+sin10cos10sin40

    =````````````````````````````+cos40(1-cos20)/2+sin20sin40/2

    =````````````````````````````+cos40/2-1/2(cos40cos20-sin40sin20)

    =1-1/2(cos20+cos100)+cos40/2-1/2cos60

    接下来再把再把cos100=-cos(20+60)带进去展开带进去算··········

    别偷懒奥哦··