Question

(1/4)^2÷(-1/2)^3+0÷2/5-[21*(3又1/7-7又1/3)*7/22÷3/1/2]^2

Answer 1

(1/4)^2÷(-1/2)^3+0÷2/5-[21*(3又1/7-7又1/3)*7/22÷3又1/2]^2

=1/16÷（-1/8）+0-[21*(22/7-22/3)*7/22÷7/2]^2

=-1/2-[（21÷7/2）*(1/7-1/3)*22*7/22]^2

=-1/2-[6*(1/7-1/3)*7]^2

=-1/2-[(6*7*1/7-6/7*1/3)]^2

=-1/2-（6-14）^2

=-1/2-（-8）^2

=-1/2-64

=-64又1/2