解
(2x-7)²-(x+1)²=0
[(2x-7)+(x+1)][(2x-7)-(x+1)]=0
(3x-6)(x-8)=0
∴x=2
或x=8
解
(x-6)²-25=0
(x-6)²-5²=0
(x-6+5)(x-6-5)=0
(x-1)(x-11)=0
x=1或x=11
解
(2x-7)²-(x+1)²=0
[(2x-7)+(x+1)][(2x-7)-(x+1)]=0
(3x-6)(x-8)=0
∴x=2
或x=8
解
(x-6)²-25=0
(x-6)²-5²=0
(x-6+5)(x-6-5)=0
(x-1)(x-11)=0
x=1或x=11