(√3-2)^2007 * (√3+2)^2008
=((√3-2)(√3+2))^2007*(√3+2)
=-1*(√3+2)
=-√3-2
∵√(x-1/x)=2,
∴x-1/x=4,x^2-2+1/x^2=16,
∴x^2+1/x^2=18,x^2+1/x^2+14=32
∴√(x^2+1/x^2+14)=4√2
由题得 x-1>0,
即x>1.
(√3-2)^2007 * (√3+2)^2008
=((√3-2)(√3+2))^2007*(√3+2)
=-1*(√3+2)
=-√3-2
∵√(x-1/x)=2,
∴x-1/x=4,x^2-2+1/x^2=16,
∴x^2+1/x^2=18,x^2+1/x^2+14=32
∴√(x^2+1/x^2+14)=4√2
由题得 x-1>0,
即x>1.