设慢车速为xkm/h,则快车速为(x+16)km/h
4(x+16)=7/12[4(x+16+x)]
4x+64=7/12[4(2x+16)]
4x+64=7/12[8x+64]
4x+64=14/3x+112/3
4x+(64-112/3)=14/3x
4x+80/3=14/3x
80/3=2/3x
x=40,(x+16)=56
(40+56)×4=384(km)
故甲乙两城相距384km
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设慢车速为xkm/h,则快车速为(x+16)km/h
4(x+16)=7/12[4(x+16+x)]
4x+64=7/12[4(2x+16)]
4x+64=7/12[8x+64]
4x+64=14/3x+112/3
4x+(64-112/3)=14/3x
4x+80/3=14/3x
80/3=2/3x
x=40,(x+16)=56
(40+56)×4=384(km)
故甲乙两城相距384km
师范附小李为您解答~
如果您满意请按下采纳,您的采纳是我前进的动力~