问几道数学简便计算题.一.1988+1987-1986-1985+1984+1983-1982-1981+…+1二·51

3个回答

  • 1988+1987-1986-1985+1984+1983-1982-1981+…+1

    =1988/4X4

    =1988

    (每相邻四项的结果为4,共有1988除以4项.不过,按规律,最后四项应该为+4+3-2-1,你那+1可能有误.)

    51又2/3*3/5+71又3/4+4/7+91又4/5*5/9

    =(51+2/3)X3/5+(71+3/4)+4/7+(91+4/5)X5/9

    =(50+5/3)X3/5+71+3/4+4/7+(90+9/5)X5/9

    =50X3/5+5/3X3/5+71+3/4+4/7+90X5/9+9/5X5/9

    =30+1+71+3/4+4/7+50+1

    =(30+1+71+50+1)+(3/4+4/7)

    =153+37/28

    =154又9/28

    (此题主要运用乘法分配律进行简便计算.)

    1+1/1+2+1/1+2+3+1/1+2+3+4+…+1/1+2+3+…+99+100

    此题题目有误,应加上括号为:

    1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+…+1/(1+2+3+…+99+100)

    =2X[(1-1/2)+(1/2-1/3)+……(1/98-1/99)+(1/99-1/100)+(1/100-1/101)]

    =2X[1-1/101]

    =2X100/101

    ==200/101

    (此题主要运用了1/2=1-1/2,1/6=1/2-1/3,1/12=1/3-1/4,1/[n(n+1)]=1/n-1/(n+1)的规律进行简便计算.)