把x=-3代入ax³-bx+3=-5得
a×(-3)³-b×(-3)+3=-5
-27a+3b+3=-5
-27a+3b=-8
再把x=3代入ax³-bx+3得
a×3³-b×3+3
=27a-3b+3
=-(-27a+3b)+3 把-27a+3b=-8代入
=-(-8)+3
=8+3
=11
把x=-3代入ax³-bx+3=-5得
a×(-3)³-b×(-3)+3=-5
-27a+3b+3=-5
-27a+3b=-8
再把x=3代入ax³-bx+3得
a×3³-b×3+3
=27a-3b+3
=-(-27a+3b)+3 把-27a+3b=-8代入
=-(-8)+3
=8+3
=11