设4X^2+2＝t
（t+1）t=12
t^2+t-12=0
(t+4)(t-3)=0
(4X^2+2+4)(4X^2+2-3)=0
(4x^2+6)(4x^2-1)=0
(4x^2+6)(2x+1)(2x-1)=0
x1=-1/2 x2=1/2
解方程,（4X^2+3)(4X^2+2)=12
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设4X^2+2＝t
（t+1）t=12
t^2+t-12=0
(t+4)(t-3)=0
(4X^2+2+4)(4X^2+2-3)=0
(4x^2+6)(4x^2-1)=0
(4x^2+6)(2x+1)(2x-1)=0
x1=-1/2 x2=1/2