2x^2-x-5
=2(x²-x/2-5/2)
=2[(x-1/4)²-(1/4)²-5/2]
=2[(x-1/4)²-41/16]
=2[(x-1/4)+(√41)/4][(x-1/4)-(√41)/4]
=2[x-(1-√41)/4][x-(1+√41)/4]
在实数范围内因式分解:2x^2-x-5=_____________
2x^2-x-5
=2(x²-x/2-5/2)
=2[(x-1/4)²-(1/4)²-5/2]
=2[(x-1/4)²-41/16]
=2[(x-1/4)+(√41)/4][(x-1/4)-(√41)/4]
=2[x-(1-√41)/4][x-(1+√41)/4]