几道因式分解(2x^2+1)^2+2(2x^2+1)+12ab-b^2-a^2+abm-m^3-mn^2+2m^2n(a

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  • (2x^2+1)^2+2(2x^2+1)+1=(2x^2+1+1)^2=4(x^2+1)^2

    2ab-b^2-a^2+ab=-a^2+3ab-b^2 题目有误,整数范围内不能分解

    m-m^3-mn^2+2m^2n

    =m(1-n^2+2mn-m^2)

    =m[1-(m-n)^2]

    =m(1-m+n)(1+m-n)

    (a^2+b)^2-4a^2b^2

    =(a^2+b+2ab)(a^2+b-2ab)

    (x^2-3)^2+(x^2-3)-2

    =(x^2-3+2)(x^2-3-1)

    =(x^2-1)(x^2-4)

    =(x+1)(x-1)(x+2)(x-2)

    2x^2+x+1 无解

    3x^2+5x+2=(3x+2)(x+1)

    3x^2+x-2=(3x-2)(x+1)

    2x^2+13x+15=(2x+3)(x+5)

    12x^2-25x+12=(3x-4)(4x-3)

    3x^2+x-10 =(3x-5)(x+2)