0
y=sin(2x-π/6) x∈(0,π )的值域
1个回答
相关问题
-
y=sin(x+π/6)+sin(x-π/6)+cosx ,x∈[-π/2,π/2]的值域
-
y=sin(2x-π/6)+2的单调区间,x∈【0,2π/3】的值域和x∈【-π/2,π/6】的值域,对称中心,y=si
-
y=2sin(2x+π/6),x属于[π/12,π/2]的值域
-
函数y=2sin(2x+π/3)(-π/6≤x≤π/6)的值域是
-
求函数的值域y=sin(2x+π/3),x∈(-π/6,π)
-
函数y=2sin(x+π/3),x属于[π/6,π/2]的值域
-
求函数y=2sin(2x+π/3),x属于(-π/6,π/6)的值域
-
求函数y=2sin(2x+3/π)(-π/6<π/6)的值域
-
y=sin(2x-π/6)在-π/12,π/2上的值域
-
函数y=2sin(x+π/6) x∈【 -π/2,π/2】的值域是(要过程)