过点A做AM⊥BC,交BD与点N,
∠ACB=∠ABC=45°
∠BAM=∠ACB=45°,∠CAE=∠ABD,AB=AC
△ABN≌△AEC,AN=CE
∠MAC=∠C=45°,AD=CD,AN=CE,
△AND≌△CED,
∠ADB=∠CDE