Question

已知x²-10x+y²+4y+29=0求x的y次方的值

Answer 1

x²-10x+y²+4y+29=0

(x²-10x+25)+(y²+4y+4)=0

(x-5)²+(y+2)²=0

x-5=0,y+2=0

x=5,y=-2

x的y次方

=5^(-2)

=25分之1