设水流速度为x,每个泄洪闸泄洪量为y,可得:
2x-2y=0.6
4x-8y=-0.1
解方程组得:
x=0.625 y=0.325
设打开5个泄洪闸,还需a小时水位可降到安全线可得:
(5x0.325-0.625)a=1.2
解得:a=1.2