Question

求1到999能被3整除，且至少有一位数字是5的所有正整数的个数

Answer 1

一共有91个。实现的C++程序如下：void testcode9(){ int count = 0;

for (int i = 1; i <= 999; i++) { bool condition = ((i % 10) == 5) || (((i / 10) % 10) == 5) || (((i / 100) % 10) == 5); if (condition && (i % 3 == 0)) { cout << i << " "; count++; } } cout << endl; cout << "The total num is " << count << endl;}最后的结果为：