Question

求y=根号下(x-1)(x-2)平方|(x-3)(x-4)平方的导数,急

Answer 1

=[(x-1)^0.5/(x-3)]*[(x-2)^2/(x-4)^2]

=[(x-1)^0.5/(x-3)]'*[(x-2)^2/(x-4)^2]+[(x-1)^0.5/(x-3)]*[(x-2)^2/(x-4)^2]'

=(2-x)*(5x+1)/[(x-1)^0.5*(x-3)^2*(x-4)^2]