设CH4、C2H6的物质的量分别为x、y
16g/mol × x + 30g/mol × y= 4.6g
(x + y)× 22.4L/mol=4.48L
解得:
x=0.1mol
y=0.1mol
1、CH4的质量=0.1mol× 16g/mol =1.6g
2、标况下C2H6的体积=0.1mol× 22.4L/mol=2.24L
设CH4、C2H6的物质的量分别为x、y
16g/mol × x + 30g/mol × y= 4.6g
(x + y)× 22.4L/mol=4.48L
解得:
x=0.1mol
y=0.1mol
1、CH4的质量=0.1mol× 16g/mol =1.6g
2、标况下C2H6的体积=0.1mol× 22.4L/mol=2.24L