找错了,应为：
x^3-3x^2+4=x^3+1-3x^2+3
=(x^+1)(x^2-x+1)-3(x-1)(x+1)
=(x+1)(x^2-x+1-3x+3)
=(x+1)(x^2-4x+4)
=(x+1)(x-2)^2=0
X^3-3X^2+4=0x^3-3x^2+4=x^3+1-3x^2+3=(x^+1)(x^2+x+1)-3(x-1)(x
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