Question

AB//GH//cD,点H在Bc上,Ac与BD交于点G,AB=2,cD=3,则GH的长为多少.

Answer 1

∵AB∥GH,

∴GH AB =CH BC ,即GH 2 =CH BC ①,

∵GH∥CD,

∴GH CD =BH BC ,即GH 3 =BH BC ②,

①+②,得GH 2 +GH 3 =CH BC +BH BC ,

∵CH+BH=BC,

∴GH 2 +GH 3 =1,

解得GH=6 5 ．

故答案为6 5 ．