已知x+2y=4且 x大于等于0,y>1/2.求满足x^2+y^2>13/4的x的取值范围
1个回答
x+2y=4
y=(4-x)/2
x^2+y^2>13/4
x²+(4-x)²/4>13/4
5x²-8x+3>0
(x-1)(5x-3)>0
∴x>1或x1/2
∴(4-x)/2>1/2
∴x
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