设x^2/a^2-y^2/b^2=1; 将两组(x,y)带入式中即{49/a^2-72/b^2=1; 28/a^2-9/b^2=1 => {49b^2-72a^2=a^2b^2; 28b^2-9a^2=a^2b^2 => b^2=3a^2,再代入上式得到a=5,b=15,所求
x^2/25-y^2/225=1
设x^2/a^2-y^2/b^2=1; 将两组(x,y)带入式中即{49/a^2-72/b^2=1; 28/a^2-9/b^2=1 => {49b^2-72a^2=a^2b^2; 28b^2-9a^2=a^2b^2 => b^2=3a^2,再代入上式得到a=5,b=15,所求
x^2/25-y^2/225=1