Question

解题求值题若（3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求a-b+c-d+e-f的值

Answer 1

令x=-1

那么a-b+c-d+e-f=-(ax^5+bx^5+cx^3+dx^2+ex+f)=-(3x+1)^5=32