Question

1.已知,根号2a-1+根号b+1=0,求4a-b的平方的值.

Answer 1

1.∵√2a-1+√b+1=0∴2a-1=0,b+1=0a=1/2,b=-1∴(4a-b)²=(4×1/2+1)²=92.∵a1=3m-1a2=13-5m而a1+a2=0∴3m-1+13-5m=0∴m=6a1=3m-1=3×6-1=17∴a=a1²=17²=289∴a+m=289+6=295