Question

（根号2002-根号2001）^2002·（根号2002+根号2001）^2001的结果

Answer 1

原式=(√2002-√2001)²ºº²×(√2002+√2001)²ºº¹

=(√2002-√2001)×(√2002-√2001)²ºº¹×(√2002+√2001)²ºº¹

=(√2002-√2001)×[(√2002-√2001)(√2002+√2001)]²ºº¹

=(√2002-√2001)×(√2002²-√2001²)²ºº¹

=(√2002-√2001)×(2002-2001)²ºº¹

=(√2002-√2001)×1²ºº¹

=(√2002-√2001)×1

=√2002-√2001