A1/A2 =c1/c2
0.350 / 0.382= [0.132/132 *2 /1L )*(10.00/50.00)] / c2
c2=4.37*10^-4 mol/L
n(NH4+)=4.37*10^-4 mol/L *(50.00/1.00)*(100.00/1000)L=2.18*10^-3mol
样品中NH4^+的质量分数=2.18*10^-3mol*18g/mol /0.1000 *100%=39.29%
N的质量分数==2.18*10^-3mol*14g/mol /0.1000 *100%=30.56%