f(x)=sinx+√3cosx =2(1/2*sinx+√3/2*cosx) =2(sinxcosπ/3+cosxsinπ/3) 2sin(x+π/3)(1)周期是k*2π=2kπ,k∈Z,此问是周期不是最小正周期振幅=2(2)令x+π/3=0,π/2,π,3π/2,2πx=-π/3,π/6,2π/3,7π/6,5π/3画出点(-π/3,0),(π/6,2),(2π/3,0),(7π/6,-2),(5π/3,0)如图
（3）
∵sinX的减区间是【π/2+2kπ,3π/2+2kπ】,k∈Z∴令π/2+2kπ<=x+π/3<=3π/2+2kπ,k∈Zπ/6+2kπ<=x<=7π/6+2kπ,k∈Zf(x)减区间是[π/6+2kπ,7π/6+2kπ],k∈Z
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