若x+y=6,xy-3,x³y+xy³=?
3个回答
x³y+xy³
=xy(x^2+y^2)
=xy(x^2+y^2+2xy-2xy)
=xy(x+y)^2-2(xy)^2
=3*6^2-2*3^2
=108-18
=90
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