因为x> 1,所以在x 1,1 /(X-1)是正的;
F(X)= X + 1 /(X-1)=(X-1)+1 /(X-1)+1,住宅因到(x-1)+ 1 /(X-1)大于或等于的平方根的2倍[(X-1)* 1 /(X-1)] = 2
BR>所以函数f(x)=(X-1)+ 1 /(X-1)1大于或等于2 +1 = 3,
已知最小则f(x)是3.
因为x> 1,所以在x 1,1 /(X-1)是正的;
F(X)= X + 1 /(X-1)=(X-1)+1 /(X-1)+1,住宅因到(x-1)+ 1 /(X-1)大于或等于的平方根的2倍[(X-1)* 1 /(X-1)] = 2
BR>所以函数f(x)=(X-1)+ 1 /(X-1)1大于或等于2 +1 = 3,
已知最小则f(x)是3.